For a double refracting crystal, the refractive indices for the ordinary and extraordinary rays are denoted by $n_0$ and $n_e$. Which of the following relations is valid along the optical axis of the crystal?Solution in Kannada

यदि एक कैल्साइट क्रिस्टल के लिए O व E-किरण के अपवर्तनांक क्रमशः ${\mu }_0$ व ${\mu }_e$ हैं, तब क्रिस्टल के प्रकाशिक अक्ष के अनुदिश

When light is incident on two refractory crystals, two refracted rays are produced by ordinary rays (O-rays) and extraordinary rays (E-rays).

For bipolar crystals, the velocities of ordinary and extraordinary rays are respectively V_0 And V_E And refractive index respectively mu_c And mu_E If so

Consider the following statement A and B and identify the correct answer
A) The refractive index of the extra-ordinary ray depends on the angle of incidence in double refraction
B) The vibrations of light waves acquire one sidedness fro both ordinary and extraordinary rays in double refraction

Consider the following statement A and B and identify the correct answer A) In the phenomenon of double refraction ordinary ray obeys Snell.s law where as extraordinary ray does not obey Snell.s law B) Velocity of extra-ordinary ray in the negative crystal is greater than for ordinary ray in the same crystal.

Consider the following statements
(A) The refractive index of the extraordinary ray depends on the angle of incidence in double refraction
(B) The vibractions of light waves acquire one -sideness for both ordinary and extraordinary rays in double refraction
(C ) Diffraction fringes will be always unequally spaced .

V_(0) and V_(E) represent the velocities, m0 and mE the refractive indices of ordinary and extraordinary rays for a doubly refracting crystal. Then

If n_e and n_0 be the refractive indices of the crystal for E-ray and O-ray respectively, then for the negative crystal which of the following relation is correct ?