If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

A simple pendulam swings with amplitude of 5 cm and time period 2 s. Calculate its maximum velocity, maximum acceleration and velocity when it is 2 cm away from its mean position.

If a simple pendulum oscillates in water instead of air then the time period will -

The motion of a simple pendulum when it oscillates with small amplitude is

A simple pendulum oscillates with an anglular amplitude of $\theta$. If the maximum tension in the string is 3 times the minimum tension, then the value of $\cos \theta$ is

A simple pendulum oscillates with an amplitude of $2\times {10}^{-2}m$. If the force acting on it at extreme position is 4 N. Then the time that another simple pendulum of length 81 cm takes to execute the same number of oscillations is

A simple pendulum oscillates in air with time period T and amplitude A . As the time passes

A simple pendulum oscillating with a small amplitude has a time period of $T=1.0s$ . A horizontal thin rod is now placed beneath the point of suspension at a distance equal to half the length of the pendulum. The string collides with the rod once in each oscillation and there is no loss of energy in such collisions. Find the new time period T of the pendulum

The equation of a simple harmonic oscillator with amplitude 5 cm and period 2 sec is if particle is starting from the mean positions is–

The time period of an oscillating simple pendulum is $1s$ when its amplitude of vibration is $4cm$. Its time period when its amplitude is $6cm$ is