What happens to the force on the rope A-C as the weight changes? O The magnitude stays the same and the angle stays the same. O The magnitude decreases and theta changes. O The magnitude increases and the angle stays the same. The magnitude stays the same and the angle changes.
What happens to the force on the rope A-C as the weight changes? O The magnitude stays the same and the angle stays the same. O The magnitude decreases and theta changes. O The magnitude increases and the angle stays the same. The magnitude stays the same and the angle changes.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 76PQ: Jamal and Dayo are lifting a large chest, weighing 207 lb, by using the two rope handles attached to...
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Transcribed Image Text:What happens to the force on the rope A-C as the weight changes?
The magnitude stays the same and the angle stays the same.
The magnitude decreases and theta changes.
The magnitude increases and the angle stays the same.
The magnitude stays the same and the angle changes.
![Coplanar forces occur within two dimensions (A plane).
In this activity, you will observe the following when the mass of the crate is changed:
1. The change in the smallest angle theta (8) without either cable failing.
2. The forces on the ropes A-C and A-B.
0
10
C
20
0
30
40
A B
---8
50
+ Fx = 0; -Fc cose + FB = 0;
0 = 0.00⁰
60
70
Fc=
10(10³N) =-
80 90
+1ΣFy = 0;
Fc sine -ON=0
Equation (2)
The maximum force in either rope AB or AC cannot exceed 10 KN without breaking. As seen in the
x-equilibrium equation, Fc is always > FB. Thus, setting Fc to 10 KN represents the load limit of the
ropes.
Substituting Fc = 10 kN into Equation (2), we get
[10 (10³)N] sine -0.00 N = 0
= sin ¹ (0.000) = 0.00⁰
The force developed in rope AB can be obtained by substituting the values for 8 and Fc into Equation (1).
FB
cos
FB
cos 0.00⁰
100 110
FB = 10.00 KN
Drag the slider to change the mass of the crate.
FD
- Equation (1)
120
=
130
F.
B
140 150
0.00 N
X
160
170 180 190 200](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2Fc9016a05-21af-452e-9927-0ef0855eba51%2Fgv6aynt_processed.png&w=3840&q=75)
Transcribed Image Text:Coplanar forces occur within two dimensions (A plane).
In this activity, you will observe the following when the mass of the crate is changed:
1. The change in the smallest angle theta (8) without either cable failing.
2. The forces on the ropes A-C and A-B.
0
10
C
20
0
30
40
A B
---8
50
+ Fx = 0; -Fc cose + FB = 0;
0 = 0.00⁰
60
70
Fc=
10(10³N) =-
80 90
+1ΣFy = 0;
Fc sine -ON=0
Equation (2)
The maximum force in either rope AB or AC cannot exceed 10 KN without breaking. As seen in the
x-equilibrium equation, Fc is always > FB. Thus, setting Fc to 10 KN represents the load limit of the
ropes.
Substituting Fc = 10 kN into Equation (2), we get
[10 (10³)N] sine -0.00 N = 0
= sin ¹ (0.000) = 0.00⁰
The force developed in rope AB can be obtained by substituting the values for 8 and Fc into Equation (1).
FB
cos
FB
cos 0.00⁰
100 110
FB = 10.00 KN
Drag the slider to change the mass of the crate.
FD
- Equation (1)
120
=
130
F.
B
140 150
0.00 N
X
160
170 180 190 200
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