A rectangular lot has 90' frontage and is 140' deep. The building setbacks are 15' front, 30' rear, and 10' on each side. What would be the maximum square footage contained in the building?

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Answer 1 · 2018-01-03T14:05:03

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The maximum width of the building would be:

#90"ft" - 10"ft" - 10"ft" = 70"ft"#

The maximum length of the building would be:

#140"ft" - 15"ft" - 30"ft" = 95"ft"#

The maximum square footage would then be:

#A = l xx w = 70"ft" xx 95"ft" = 6650"ft"^2#

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