Other Parts Discussed in Thread: TPS7B81-Q1
Hello all,
In my design, I'm using the TPS79933 LDO
I was looking for the output rise time in order to make there is no significant inrush current at startup.
I came across this graph which shows the output voltage rise time at Vout=3V + Cout=10uF
something is a bit weird...
It looks like the rise time is about 20usec, and using the I=c*[dv/dt] formula, and I get an input current of (I'm neglecting Rout-19ohm):
Iout=10*10-6* [3/20*10^-6]
Iout=1.5A
How can the LDO support this current level, if the internal current limit is 600mA max?
Thanks!
Nir