Plastic insulation surrounds a wire having diameter d and length l as shown above. A decrease in the resistance of the wire would be produced by an increase in the:
[1 Mark]

(a) length l of the wire
(b) diameter d of the wire
(c) temperature of the wire
(d) thickness of the plastic insulation

Open in App

Solution

Solution:
Correct option: B, diameter d of the wire [1 Mark]
Resistance is directly proportional to the resistivity of the material, and length of the wire. It is inversely proportional on the Area of the wire. Therefore, the resistance of the material would only decrease with an increase in area. This can be done by increasing the diameter.

Suggest Corrections

Similar questions

4 Ω

p l a s t i c = 0.16 \times 10^{- 2} c a l / s c m^{\circ} C

2 m

4 o h m

0.64 m m

0.06 m m

5 A

K = 0.16 \times 10^{- 2} c a l / c m^{\circ} C s e c

150

100

Does the resistance of a copper wire increase or decrease when both the length and diameter of the wire is doubled? Explain your reasoning.

Join BYJU'S Learning Program