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Byju's Answer
Standard IX
Chemistry
Hydrated and Anhydrous Substances
For two react...
Question
For two reactions in equilibrium in same container() A(s)2B (g) + C(g); (K,), = 27 atm3(ii)D(s)2B(g) +E(g); (Kp)= 81 atm3Pressure of B(g) at equilibrium will be(1) 6 atm(2)3 atm(3) 5 atm(4) 9 atm
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Q.
A
(
s
)
⇌
B
(
g
)
+
C
(
g
)
K
p
=
40
a
t
m
2
X
(
s
)
⇌
B
(
g
)
+
E
(
g
)
Above equilibrium is allowed to attain in a closed container and pressure of
B
was found to be
10
a
t
m
. Calculate standard Gibb's free energy change for
X
(
s
)
⇌
B
(
g
)
+
E
(
g
)
at
300
K
(
t
a
k
e
R
=
2
c
a
l
/
K
/
m
o
l
)
Q.
The equilibrium constant
K
p
for the reaction
A
(
g
)
⇌
B
(
g
)
+
C
(
g
)
is 1 at
27
C
a
n
d
4
a
t
47
.
For the reaction calculate enthalpy change for the
B
(
g
)
+
C
(
g
)
⇌
A
(
g
)
(
G
i
v
e
n
:
R
=
2
c
a
l
/
m
o
l
−
K
)
Q.
Assertion :For the reaction
A
(
g
)
⇌
B
(
g
)
+
C
(
g
)
,
K
p
=
1
a
t
m
. If we start with equal moles of all gases at 9 atm of initial pressure, then at equilibrium partial pressure of A increases. Reason: Reaction quotient
Q
p
>
K
p
hence equilibrium shifts in a backward direction.
Q.
For the equilibrium
A
(
g
)
⇌
B
(
g
)
+
C
(
g
)
;
K
p
=
0.82
atm at
27
o
C. At the same temperature, its
K
c
in mol
l
i
t
−
1
is:
[
R
=
0.082
lit atm
m
o
l
−
1
K
−
1
]
Q.
The equilibrium constant
K
p
for the reaction
A
(
g
)
⇌
B
(
g
)
+
C
(
g
)
is
1
at
27
o
C
and
4
at
47
o
C
. Calculate enthalpy change for:
B
(
g
)
+
C
(
g
)
⇌
A
(
g
)
(Given
R
=
2
c
a
l
/
m
o
l
.
K
).
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